The & operator is no different to other operators when used on a reference: in all cases, the reference is dereferenced first. So
int i;
int &r = i;
int *p;
p = &r;
gives you a pointer to i in p. &r dereferences r, to get i, before taking its address.
Anti-nuisance lawsuit warning: The purpose of these notes is to remind me, Zoegond, of stuff or to help me work stuff out. They may contain mistakes.
Quick
- ($a, $b....) = unpack("A2A7...", $packed)
- push( array, list )
