Even in this scenario where b and c are both byte variables
c = b + 64;
C# converts the result of the calculation to int, and then complains that you're assigning int to byte. Casting 64 to (byte) doesn't help either, you have to say
c = (byte) (b + 64);
ffs.
Anti-nuisance lawsuit warning: The purpose of these notes is to remind me, Zoegond, of stuff or to help me work stuff out. They may contain mistakes.
Quick
- ($a, $b....) = unpack("A2A7...", $packed)
- push( array, list )
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